2x^2-90x+148=0

Solution for 2x^2-90x+148=0 equation:

2x^2-90x+148=0

a = 2; b = -90; c = +148;
Δ = b2-4ac
Δ = -902-4·2·148
Δ = 6916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6916}=\sqrt{4*1729}=\sqrt{4}*\sqrt{1729}=2\sqrt{1729}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-2\sqrt{1729}}{2*2}=\frac{90-2\sqrt{1729}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+2\sqrt{1729}}{2*2}=\frac{90+2\sqrt{1729}}{4}
$